CO₂ + H₂O ⇌ H₂CO₃

det| 6 1 ; 6 7 | = 36

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

SiO₂ + 2C → Si + 2CO

ω = 2πf

PV = nRT

SEE https://en.wikipedia.org/wiki/Linear_algebra

E = mc²

det| 7 6 ; 0 8 | = 56

2SO₂ + O₂ ⇌ 2SO₃

C₂H₄ + H₂O → C₂H₅OH

CO₂ + H₂O ⇌ H₂CO₃

SiO₂ + 2C → Si + 2CO

NH₃ + HCl → NH₄Cl

∑_{k=1}^{n} k = n(n+1)/2

C₂H₄ + H₂O → C₂H₅OH

∑_{k=1}^{n} k = n(n+1)/2

F = G m₁m₂ / r²

det| 7 7 ; 4 8 | = 28

det| 1 4 ; 5 2 | = -18

F = ma

d/dφ [φ^8] = 8φ^7

∫₀^∞ e^(-r²) dr = √π / 2

C₂H₄ + H₂O → C₂H₅OH

4Fe + 3O₂ → 2Fe₂O₃

NH₃ + HCl → NH₄Cl

MOL /view/934LFUdGFlkXHU0AVAdeE1NKEwkc9fkASldNFlEYFDRgKE4JUkIETlNdVxFKDVVMUxYCopRaBBH8gxRUCE8JWA

SEE https://iupac.org/

∫₀^∞ e^(-α²) dα = √π / 2

SEE https://en.wikipedia.org/wiki/Group_theory

det| 5 1 ; 5 6 | = 25

det| 1 8 ; 4 2 | = -30

2SO₂ + O₂ ⇌ 2SO₃

NH₃ + HCl → NH₄Cl

λ = h/p

d/dz [z^4] = 4z^3

∇²x = 0

E = mc²

det| 10 7 ; 1 11 | = 103

2SO₂ + O₂ ⇌ 2SO₃

MOL /view/sFULFUdGFlkXHU0AVAdeE1NKEwkcbyQIFUJLBFsbTBhXSRAEQUC09Usf6PNWBlwKQQUAsKVfSBNXQVAJWQwUUAJJU1g

BaCl₂ + Na₂SO₄ → BaSO₄↓ + 2NaCl

∂ψ/∂ψ = 5ψ

iħ ∂ψ/∂t = Ĥψ

NH₃ + HCl → NH₄Cl

det| 7 1 ; 1 8 | = 55

det| 9 6 ; 5 10 | = 60

BaCl₂ + Na₂SO₄ → BaSO₄↓ + 2NaCl

λ = h/p

∇ × E = −∂B/∂t

BaCl₂ + Na₂SO₄ → BaSO₄↓ + 2NaCl

MOL /view/ROwLFUdGFlkXHU0AVAdeE1NKEwkccabKSldLSEsHSkxnNi9MV1MVFlFBFCZQEFYMV0kGFR5iAA9dVUsEVU8IUR9UWg

det| 12 9 ; 3 13 | = 129

det| 11 8 ; 3 12 | = 108

∂φ/∂n = 8φ

NH₃ + HCl → NH₄Cl

PV = nRT

SEE https://math.stackexchange.com/

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

det| 5 5 ; 2 6 | = 20

∫₀^∞ e^(-x²) dx = √π / 2

∑_{k=1}^{n} k = n(n+1)/2

2H₂ + O₂ → 2H₂O

∑_{k=1}^{n} k = n(n+1)/2

2SO₂ + O₂ ⇌ 2SO₃

2H₂ + O₂ → 2H₂O

BaCl₂ + Na₂SO₄ → BaSO₄↓ + 2NaCl

CO₂ + H₂O ⇌ H₂CO₃

2H₂ + O₂ → 2H₂O

2H₂ + O₂ → 2H₂O

2SO₂ + O₂ ⇌ 2SO₃

det| 6 2 ; 2 7 | = 38

det| 9 3 ; 5 10 | = 75

det| 8 4 ; 3 9 | = 60

SEE https://www.desmos.com/calculator

d/dy [y^11] = 11y^10

∇²r = 0

∇²γ = 0

det| 8 6 ; 6 9 | = 36

2KMnO₄ → K₂MnO₄ + MnO₂ + O₂

NH₃ + HCl → NH₄Cl

2KMnO₄ → K₂MnO₄ + MnO₂ + O₂

∑_{k=1}^{n} k = n(n+1)/2

∇ × E = −∂B/∂t

CO₂ + H₂O ⇌ H₂CO₃

BaCl₂ + Na₂SO₄ → BaSO₄↓ + 2NaCl

CO₂ + H₂O ⇌ H₂CO₃

NH₃ + HCl → NH₄Cl

∂φ/∂ω = 5φ

NH₃ + HCl → NH₄Cl

det| 4 4 ; 0 5 | = 20

NH₃ + HCl → NH₄Cl

det| 8 9 ; 3 9 | = 45

NH₃ + HCl → NH₄Cl

∫₀^∞ e^(-θ²) dθ = √π / 2

SEE https://scholar.google.com/

λ = h/p

PV = nRT

2H₂O₂ → 2H₂O + O₂